В сосуде смешиваются три химически не взаимодействующих
1. . 2. . 3. 1 – 93 . 3-1. . 3-2. . 3-3. . 3-4. . 3-5. . 3-6. . 4. 2 – 56 . 4-1. . 4-2. . 4-3. . 4-4. . 4-5. . 4-6. . 5. – 52 . 6. . 7. .
1 1-9 , m1 = 1 , m2 = 10 , m3 = 5 t1 = 6o, t2 = 40o, t3 = 60o; 1 = 2 /(), 2 = 4 /(), 3 = 2/(). Θ . : m1 = 1 , m2 = 10 , m3 = 5 , t1 = 6o, t2 = 40o, t3 = 60o, 1 = 2 /(), 2 = 4 /(), 3 = 2/(). Θ – ? Q1 + Q2 + Q3 = 0 (1), Q1 = 1 m1(Θ – t1) – ; Q2 = 2 m2(Θ – t2) – ; Q3 = 3 m3(Θ – t3) – . Q1, Q2 Q3 (1): 1 m1(Θ – t1) + 2 m2(Θ – t2) + 3 m3(Θ – t3) = 0, , 1m1Θ – 1m1t1 + 2 m2Θ – 2 m2 t2+ 3m3Θ – 3m3 t3 = 0, 1-18 t1= 15 L1 = 1 . t2 = – 35? : t1= 15, L1 = 1 , t2 = – 35. ΔL – ? ΔL = L1 L2, , , L1 = L(1 + αt1) (1) L2 = L(1 + αt2) (2). L – 0, L2 – t2 , α = 1,210-5 -1 . : ΔL = L1 – L2 = L(1 + αt1) – L(1 + αt2) => ΔL = Lα(t1 – t2) (3). (1) L = L1/(1 + αt1) (3), , αt1 << 1, (4) : ΔL ≈ L1 α(t1 – t2 )(1 – αt1) ≈ L1 α(t1 – t2 ) = 610-4 . 1-32 V = 100 t = 27 1 = 30%. 2, m = 1 ? t = 27 = 3,55 . : V = 0,1 3, t = 27, 1 = 30%, m = 0,001 , = 3,55103 . 2- ? 1: ρ1 = p1μ/RT, 1 = 1 ( ), ρ1 = 1pμ/RT. Δρ = m/V ρ2 = ρ1 + Δρ = 1pμ/RT + m/V . :
2 2-7 m1 = 200 m2 = 130 t = 0o. Θ, m3 = 25 t1 = 100o? r = 2,48106 /, λ = 335103 /. : m1 = 0,200 , m2 = 0,130 , t = 0o, m3 = 0,025 , t1 = 100o. Θ -? , . , – Q2 Q4 . , Q4 = m3r = 0,025 2,3106 = 57,5103 . , Q2 = m2λ = 0,130 330103 = 42,9103 . Q4 > Q2 , 0 < Θ < 100. . Q1 = cm1(Θ t) , t Θ. Q2 = m2λ – , . Q3 = c m2(Θ t) – , , – , t Θ. Q4 = – m3r – , . Q5 = cm3(Θ – t1) – , , , t1 Θ. : Q1 + Q2 + Q3 + Q4 + Q5 = 0 (1) Q1 – Q5 (1): cm1(Θ t) + m2λ + c m2(Θ t) – m3r + cm3(Θ – t1) = 0 => => cm1Θ – cm1t + m2λ + c m2Θ – c m2t – m3r + cm3Θ – cm3 t1 = 0, 2-20 ΔL = 15 . t= 0 ? α= 2,4010-5 -1, α = 1,7010-5 -1. : ΔL = 0,15 , t= 0. L- ? L- ? t : L= L(1 + αt ) (1) L= L(1 + αt ) (2), α α – . ΔL = L – L = L- L . , : ΔL = L – L (3). (1) (2): L- L= L – L + L αt – L αt , (3) ΔL= – ΔL+ L αt – L αt , L α = L α (4). (3) (4) L L . (3): L = L – ΔL (5) L (4), L α – ΔL α = L α,
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